HW on Bayes: Draw trees,
compute. Make
a table if you think it adds to your understanding.
--Handout: "#2" (lefthanded
families). Make a tree and a table, with all
probabilities.
(You should get P(L)=.092, P(Neither|L) = .529)
--Moore&McCabe 5th ed,
p. 323
ff. You did and kept 4.104, 105 using trees. Now do
4.106, 107.
A. Hand this one in! (Monday if you need the time.
Work with anyone...) With Handout--the probabilities
are now different--the tests have improved. The issues are
similar. All positive screening results still should be confirmed
with a much more accurate test (usually the "Western blot?").
A test for HIV antibodies in mouth fluids (OraQuick) that
gives results in half an hour is now used in quick screening
contexts.
(http://aidsinfo.nih.gov/ContentFiles/FDA-3-3-06.pdf) " The
labeled sensitivity of the test is 99.3%... and the specificity is
99.8%...[Specificity may actually be lower in some circumstances:]
99.1%" . Remember sensitivity is P(test pos|antibodies yes) and
specificity is P(test negative |no antibodies). Let's use
99.1% for the specificity.
a) Assume the proportion of the people with HIV antibodies in the
population you're interested in is 1%. Make a tree, and a table
if you like. What is the probability an individual chosen at
random tests positive? If an individual chosen at random tests
positive, what is the probability (s)he actually has HIV
antibodies? If an individual chosen at random tests negative,
what is the probability (s)he is actually HIV free?
b) Repeat the analysis where the proportion in the population
with HIV is x%. Then answer the questions for x = 0.1% (say a
blood donation drive population). For x = 10% (say a
(non-celebrity) drug rehab clinic population).
Optional: M&M p. 327, 4.109-110 are very interesting. Read the problems for the flavor, at least.
--Ash sec. 2-1, p. 44
Add to 3a from last time: 3b.
4, 6
= = = = = = = = = = = = = = = = =
Bayes' type problems, continued. (Recap Day 7)
Bayes' theorem: Don't memorize
the
theorem, just know the process.
From knowing an outcome W, find the probability of an antecedent
S.
P(S | W) when W|S is the
direction
you have information for.
These can always be modeled effectively with a tree, S on the
first branching, W on the second:
Find the probability of the outcome W by summing
the "fav" tree path results. (Ash's "total probability" p. 58)
Note the probability of (S and W): just the single
path with S followed by W.
Divide: (SandW path) / (sum of W paths)
= P(S and W)/P(W) = P(S|W)
Handout Death penalty (#3)
: Given proportions of murders who got the death penalty, and for
those who did and didn't, what proportion murdered White victims.
Desire: P(Death sentence| Victim White) = P(D|W). From handout
tree we see
P(W) = (30+184)/326. P(D and W) = 30/326. P(D|W) =
30/(30+184) = 30/214 = .14
We want to compare this with P(Death sentence| Victim not white) =
P(D|B) = 6/(6+106) = 6/112 = .05 (Radelet's claim is roughly
correct)
| Race |
of | victim | |||
| W | B |
total | Numbers are used in the table,
rather than probabilities. Bold are the numbers given in the
question. The others are found by making the totals work. |
||
| death |
D | 30 | 6 | 36 | |
| life |
L | 184 | 106 | 290 | |
| total | 214 |
112 | 326 |
| Sievers home | Math300-Sp08/Day8p8.htm | 9pm | 2/12/08 |