| Hand in Monday .. = = = = = Probability , Ch. 10, discrete,. p. 261, 10.16 Grades RV p. 252, 10.6 and 10.7 D&D, 4-sided dice (These are "just like" the 6-sided dice in examples 10.4-5, with a little added twist.) On a separate sheet, simulations using
http://www.whfreeman.com/bps4e
"Probability " applet: If you do it jointly, one sheet for both
people (I'll aggregate the results) Postpone the rest:
Continuous sample spaces: p. 259, 10.15 Iowa Test Scores p. 269, 10.49 Did you vote? p. 269, 10.51 NAEP scores p. 269, 10.53 Friends |
Read, to discuss
|
Optional |
Bare Bones recap: Chance
behavior
(a random phenomenon):
Unpredictable
in the short run, predictable regular pattern
in the long run.
"Probability"
of particular something
happening:
proportion
of times it would happen in a very long series of (independent)
repetitions
of the phenomenon.
Applet: Probability
Probability
Models
: (p. 250-256)
Random phenomenon,
described by
Sample space S: set
of all possible outcomes (no overlap of descriptions)
Event: any
outcome
or set of outcomes
Probability model:
S, and a way of assigning a probability to each event.
Sample space depends on what you want to know:
Phenomenon: Flip coin twice.
S1 = {HH, HT, TH,
TT} S2 = {0, 1, 2} number of
heads
S3 = {Y, N} both are heads?
We looked at the probabilities for these,
implicitly using the "common sense" rules for proportions just below.
Probability rules: pp. 253, in
words, then in notation.
A an event in sample space S, P(A)
is "the probability
that A occurs"
These rules are all true for
proportions
in long run (Probabilities), proportion of counts,
proportions of areas.
1. 0 <
P(A) < 1
(any probability is a number between 0 and 1. )
2. P(S) = 1
(all the outcomes together have total probability 1)
3. A and B
are
disjoint if they have no outcomes in common (can't happen
simultaneously.)
If
A and B are disjoint, their probabilities add: P(A or B) =
P(A)
+ P(B)
4. For any
event A,
P(A
does not occur) = 1 - P(A)
Discrete models: Assign a probability to each outcome (>0) so they add to 1. Prob. of an event is sum of prob's of its outcomes.
Homework questions? Day 25
Questions on exam material?
New material (not on exam:)
Random Variable: Day 24 (X, Y, Z...) Variable whose value is a
numerical outcome of a random phenomenon.
Probability distribution of X tells us
what values X can take and how to assign probabilities to them.
If X has a finite number of
possible values (Discrete distributions), nothing new except
notation.
P(X < 2) is "Prob.
that X is less than 2."
Probabilities
follow the "common sense" rule for proportions of a whole. Same
rules for proportions of areas, proportions of counts, proportions in
histograms, proportions of times in the long run something would
happen.
Two principles for assigning probabilities:
--Sometimes, a properly chosen sample space will have equally likely
outcomes. You can use this to find other probabilities.
--If you pick an individual at random from a population, the
probability that one individual will be XYZ is the same as the
proportion of XYZ's in the population.
Example of an equally likely sample space, which can be used to find probabilities for another: p.251, Examples 10.4, 5, Two dice.
Another probability example: Recall exercise 8.10,
sample of managers.
How many East Asians did you
get in a sample of size 6? Day 25
Start here Monday.
This was a Teaser for Ch. 11: We know that a sample from a
population will not exactly represent the population. If
we take a random sample, the behavior of samples will not
be individually predictable, but there will be predictable
pattern in many random samples from the same population.
Knowing the pattern (here the probability distribution) will be
as good as we can do.
- - - - - -
So far, everything was for Discrete sample spaces (you can
list the outcomes) Now:
Looking ahead (back)
Random variables with intervals
of outcomes ("continuous") Ch.10 (p. 256 on)
If the sample space is an interval of values (or the whole
line), the way we assign probabilities to events is with a density
curve (Ch. 3, cf. Day 5 on) (remember density curves were idealizations of
histograms--of repeating the "experiment" many many times)
P(a < X < b) = the
probability that X is between a and b is the
area under the density curve, between a
and b.
We declare P (X = a) = 0 , so P(a < X < b) = P(a
< X < b)
Notation: Use capital letter for the random variable, the "label"
of the phenomenon. Use small letters for particular values it can
have. But this rule is often broken--Moore uses x-bar where many
(I) would use X-bar.
HW: For A and B, Use Densities Handout, from
Day 5,7. Answers to old questions
Change language from "description of a population of data" to "pick an
individual from the population, call the value X"
A. ("Uniform") X = number the spinner points to.
a) (example) The probability that the spinner points to a number
less than .6 = P( X < .6) = .6 .
b) P (.2 < X < .6) = ? Say
it in words: ?
c) For what x is there probability .4 of being greater than x
? (In notation: P(X > x) =
.4. Find x)
B. Y = (number you get from) the sum of two spinners.
("Triangular") This is the same random variable as Y in
10.14, p. 259!
a) The probability that the sum is a number less than .6 =
P( ?
) =.18 P(Y > .6) = ?
b) P(Y < 1.6) = ?
P (Y < 1) = ?
P( 1 < Y < 1.6) = ?
c) P(Y > x) = .92 Find x: ?
(Hint: P(Y<x) = .08)
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
- - - -
Our most important probability model: NORMAL
DISTRIBUTION family. Same techniques as before, only we ask
"probability that one chosen at random..." instead of "proportion of
all..." Review Normal techniques: Day 7,
Day 8 cover it all.
Take a random sample of size 1 from a population which
is N(110, 25).
(Give an individual, chosen at random, the "Classic IQ
test", which has a normal distribution, mean 110, s.d.
25. X is the score on the test.)
Find P(100 < X < 145), prob. that individual gets between 100
and 145. (in class?) Work
is on Day 8, what proportion.
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