Math 151 , Day 33, Friday, Nov. 10, 2006 After class hit reload..

HW Day33  Finish Ch. 14.  Next, Ch. 16,  p. 387-391 (ignore "tests" for now).  Check p. 405, 16.19, 21, 22, 23, 25, 26  Read ahead, Ch. 15, first to p. 364, then to p. 376.
Start reviewing:  Chapter 17, skip fig. 17.4 tonight.  Summary skills p. 414:  Test a week from today will cover C5 (continuous) and C6, D, E, H, and possibly I1,2.
Hand in Monday: 

A.  New Shoeboxes: On a Separate sheet:  (2 shoeboxes. )The shoeboxes are outside my door if you missed doing them in class. For each sample of size  4 from a shoebox, write down the values, find the mean, (know which box you got them from: White #s, green box. Yellow, red top.) and tell whether you believe the population mean for that box is 20, or something bigger. (Your gut feeling.) Does it help to know that the standard deviations for the shoeboxes are both 4? ( Bring your sample numbers and xbars  to class  to pool.)   (This is related to Chapter 15, where we'll learn the formal methods.)

<>- - - - - - - - - - - - - - - - - - - - - - - - - 
p.352, 14.4 Using Table A to find z*   The trick is to change from "C in the center between -z* and +z*" to "What? to the left of z*", to use Table A.  You can check using the C to z* section of the Confidence Interval Excel sheet.
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Sample size for C.I. (& review of CI computations)You can check using the bottom section of the Confidence Interval Excel sheet.
p. 356, 14.10 Estimating mean IQ
p. 358 14.24 Hotel managers
p. 360, 14.33 calibrating a scale

"Why C.I. formula works"
p. 348, 14.1 density of x-bar, and confidence intervals. This problem has you illustrate the middle paragraph of Example 14.2, pp. 345-6. For part c, to draw the confidence interval:  just choose any point on the horizontal axis of  your graph to be x-bar (Like me at the board, my head being xbar).  Measure off the distance m (half the width of the shaded interval) and extend a bar m wide to the left and the right of your point,below the curve (My arm length was m).  (Like fig. 14.3, one of the bars with arrows at the ends.  The red dots show what the x-bar is for that confidence interval)  Choose another point, and repeat..  If your first x-bar was in the shaded interval, pick your second outside the shaded interval, and vice versa.  You should note that if x-bar is in the shaded interval, then the confidence interval bar covers mu (280) and if x-bar isn't, then the bar doesn't.

A few review problems:
p. 419, 17.7 Day care, parameter or statistic
p. 422, 17.27 and 28 means vs. individuals.  In #27 , they're taking the "about what range" to be the interval containing the middle 99.7%--almost all.
p. 421, 17.26 WAIS, n = 1, n = 60

In practice, Ch. 16
p. 392, 16.4 holiday spending
p. 406, 16.29 hotel managers again.
p. 407, 16.33 nuke them
p. 408 16.36 sensitive questions
p. 408 16.37 college degrees

Looking ahead in Ch. 15 Try this one, on a separate sheet; will be assigned Monday.
p. 364, 15.1  Anemia

& & & & & Leftover problems from Day 30 & & & & & & & &
  Postpone once more:              These ideas are related to those in Ch. 15.
p. 290, 11.39 Pollutants in auto exhausts  For 11.39:  You might want to know L so that if you tested your 25 cars and found a high value of x-bar, you would be able to compare it with L; if it was greater than L, you would go back to the manufacturer and say "I  believe you sold me a batch of bad cars, because the chances of getting an average emission level this high if the exhaust system is working properly is only 1 in 100. It is more reasonable to believe the exhaust system is not working, than that we "are" that 1 in 100 possibility."
  p. 290,  11.38 Glucose testing  If we use this cutoff level L to say that people (with a mean of 4 tests) over L "have diabetes", then the chances of declaring that someone "has diabetes" when they really are OK (with mean 125mg/dl) is .05.  .05 or 5% is the chance of a "false positive" using this protocol, when the real mean is 125.
& & & & & & & & & & & & & & & & & &
Exam 3 will cover no farther than the above.

Read, 
to discuss

p. 391, 16.3 environment

p. 407,  16.31 sampling at the mall

Optional


(more practice)
p. 389, 16.1 TV poll

p. 391, 16.2 red lights

New Shoeboxes: Take 4 from each, write them down (White from green box, yellow from red-top box) For HW, find means (for each box separately.)  Know  which box!  Does that box have pop. mean 20, or some number >20?  Your gut feeling.  (Does it help to know s.d. for each box is 4?

Exam 4, Friday Nov. 17, Day 36. A week from today.  As usual: One sheet of notes; I will give you tables.  Covers Ch. 10 p. 257 on (Continuous models and R.V.'s), Ch. 11 up to p. 286 only, Ch. 14, Ch. 16 to p. 391, Ch. 15 to p. 364.  Sample exam  handed out today. You can do all but possibly 3d after tonight's HW (3d is like 15.1); solutions available Monday.
# # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # #
Confidence interval estimate of a(n unknown) population parameter:

Review 14.34 and 14.35 , p. 160.     
     14.35:    T = true value of parameter,  * = value of this statistic  * = results of other surveys
                                          ** ** *
                         * * ***  ***T** *** ** *     
Clustering will be around True value, not around the one we got this time.
Confidence Interval of the form  estimate + margin-of-error  for the mean µ with Confidence level C: (p.349-50) (Table A, or Table C, t dist. bottom row) The Birkenstock box contains numbers from a normally distributed population, with population standard deviation 2.
You each constructed a 60% confidence interval for the unknown mean:     n = 4.  Margin of error m is .841 x 1= .841.
How many people captured the true mean?
( previous classes, 11/20 = 55% ,  22/29= 76%.   9/18 = 50% , 11/20 = 55%,  15/22= 68%,  16/24 = 67% ,
16/18 = 88%,   7/13 = 54%Combined, 107/164 = 65%  This class:  8/16 = 50% Combined, 115/180 = 64%
Homework questions?  Day 32
   Tradeoffs: for sharper (narrower) margin of error, must  accept lower confidence level, OR take larger sample.

Planning ahead:  Choose sample size big enough to satisfy desired: margin of error, confidence level.
Given C and m = margin of error,  (and sigma), find n.
   Method:  Use C to find z*.  Plug in to formula for m, and solve for n.  Or memorize formula for n and plug in to it.
,    n = (z* sigma / m)2
     Note:  z* sigma still on top.  m and n change places, and whole thing is squared!
           Round up!  If you get n = 5.06, you need a sample of size 6 to get your margin of error at least as short as you want.
                      ConfidenceInterval.xls  Excel spreadsheet will check your calculations.  Show your work on HW!

Still need to do this:
Look back
at 11.36 and 38, p. 290.  38: "backward normal" problem.  From a proportion/probability, find a z*, from that a raw value (here an x-bar.

Why does the formula work?

In practice: pp. 388-391
SRS--other random samples get other formulas. 
   Nonrandom or biased  samples simply can't do C.I.

    Sometimes we can plausibly think of data as SRS from large population (rolling dice, repeated weighings on scale)
     -- For experiments, randomizing into groups allows us to use the methods; but be careful about generalizing far beyond our "volunteers" type.
     Ask how reasonably "like" a SRS the sample is.

Xbars are  normal!  OK IF 1) population is normal, or 2) n big enough for Central Limit theorem.
    Outliers?  Trouble (xbar is sensitive).   Slight outliers ok (see next)
    Skewness?  "Moderate" sample size allows CLTh to overcome all but strong skewness. (Numbers in Ch. 18)
Sigma for population is known.  Rarely true in practice. 
          Large n? Could substitute s calculated from sample as "good" estimate of sigma.
          Small n--Ch. 18, a slight modification of these methods takes care of unknown sigma.

~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
Start significance tests Monday
Ch. 15:  "Significance tests use an elaborate vocabulary, but the basic idea is simple: an outcome that would "rarely" happen if a claim were true--is good evidence that the claim is NOT true." (p.363 top)
Suppose someone claims that the average height of Wells women over the years is 70" (5'10").  I take samples (151 classes) every year.  This year my sample has mean 62.81" (n = 20ish). Standard deviation for heights of women in population is supposed to be about 2.5"  IF the real mean is 70", my sample is extremely improbable.  Conclude the claim is Not true.

Need machinery to analyze less "obvious" results, build in effect of standard deviation (if s.d. were 10" would my sample still be inconsistent with the claim?) and sample size (if n were only 4 would that change my result?) .  Do 15.2 p. 363 if time.


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