Review discrete
situation, into continuous
Density method: fY(y) dy =
Area = fX(x) dx. Solve for fY(y)
CDF method: FY(Y
< yo) = P(Y < yo)
= P(g(X)
< yo). Restate so it is a statement about P
(? X ?). Use the distribution of X, and whatever
means is easiest to get this into a formula, either for FY or for fY.
Homework questions?
Try again...
= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =
= = = = =
Next: Two random variables "jointly distributed".
Ash Ch. 5. First 5.1 and 5.2
In practice: Two random variables X, Y) measured on the same
experiment.
We've looked at discrete already (balls and chips in urns, tables in
two rooms in a restaurant, two dice).
Sample space: points in x-y space.
Discrete (p. 180): joint probability function p(x, y)
= P(X = x and Y= y): lump of probability sitting on that spot.
Probability of a set: Sum the
probabilities
of the points in the set.
Continuous (p. 171 ff) Joint density function f(x, y)--a surface
above the base x-y space.
Probability of a region R in x-y space= area
under f(x,y) and above the region.
Need calculus for that:
The
dA
is a little region in x-y space--you chop the x-y plane into little
dA's
and sum the volumes over all the little dA's that are in R.
How to calculate? Chop into rectangular dA's by chopping
the x axis into dx's and the y axis into dy's and making the grid. Then
you can sum them by first summing in (say) the x direction, and then
summing
those values in the y direction.
Discrete
analog:
To find the probability of the whole space:
First sum across the x direction, get P(Y=1) = 7/20, P(Y=2) =
6/20, P(Y=3) = 7/20,for each y.. Then sum over the y values, to get
(7+6+7)/20
=1.
To find P(X + Y < 4): In the yellow region, Sum
across
the x direction, get 4/20, 3/20, 3/20 for y = 1,2,3. Then sum
over
the y values to get 10/20.
Integrals:

In the inner integral, the "other" variable
acts
like a constant. Try it with f(x,y) = y

New HW Practice
here: http://www.math.temple.edu/~cow/
Calculus Book III > 5.Integration > 2.Double Integrals >
Modules 1 and 2 Double integrals over rectangles (Module
1 tells you the limits of integration and steps through. Module 2
has you set the limits and do the whole thing.
Don't worry if you can't compute all the indefinite integrals, do
enough
to understand the pattern, and skip sin and cos if you want.) Do at
least Module 1:
1, 10, 12, (recall ea+b = eaeb),
Module 2: 1, 9
Module 3 Limits of double integrals--Figuring out the limits
of integration. Caution--some problems can be done easily both
ways,
and the package will allow you to do either. But if there is only
one way to do it without breaking it into 2 double integrals, it won't
tell you you've chosen an impossible way--it'll just keep
rejecting
your answers. (e.g. Problem 1--if you (foolishly) try to integrate over
x first, you need to break the area into 2 pieces, at the line y =
1.
The integration limits are "between y/2 and y for
0<y<1,
and between y/2 and 1 for 1<y<2 ", which the program has no way
of
reading or understanding.) Copy the sketch at the first step, to
help keep track.
Don't worry about ones where you can't
guess what the indefinite integrals are.
Do as many as you need to. At least 1, 5, 12. Ash pp. 165-69 is a good
followup here.
Module 4 Changing the order of integration. This requires
figuring out from the integrals what the shape of the region is and the
functions defining the borders. Then switching, using the methods
of module 3. A good test for your understanding. Try a few,
at least 1, 4, 12.
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