Math 300 , Spring 2002, Day39, F, May 3Hit reload to get most current versionAfter class

Continuing with Two random variables X, Y "jointly distributed".  Ash 8.1
In practice: Two random variables X, Y  measured on the same experiment.
Sample space:  points in x-y space.
   Probability of a region:  sum or integrate over the region.
Continuous (p. 171 ff + Probability Handout) Joint density function f(x, y)--a surface above the base x-y space.
    Probability of a region R  in x-y space= area under f(x,y) and above the region.
The total probability (area) has to = 1.
"Marginal" probability/density function:

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 Visualizations:  (Mac 110 Black or Gray: Class Materials/Math 300/For300 Class (DPGraph program is in Math 300 folder)
f(x,y) = x+y, 0<x<1, 0<y<1.   Cardboard model.
     fX(x) = x + 1/2, 0<x<1
Probability Handout problem #17:  Density f(x,y) = Cx(1-y), 0<x<1, 0<y<2.
   Found C = 1/2.  Found fX(x) = 2x, 0<x<1.   fY(y) = (1+y)/4, 0<y<2.
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Conditional distributions: Assuming a particular x value is true/known (xo),  what is the distribution of Y?
 Continuous:  same formulas as discrete, integration instead of sums.
   Think of slicing through the joint density at xo--look at f(xo,y)--the slice.
   The conditional density fY|x(y|xo) has the shape of the slice, but the slice may not have area 1.
              If we divide by  fX(xo), it will.
The conditional probability density of Y given xo:
        fY|x(y|xo) = f(xo, y)/fX(xo)
   For a single particular number x, you can plug in that number, and then everything is in y.
        For a particular number x, integrate (sum) over all the y's.  The integral over the y's of f(xo,y) = fX(xo).
             So the sum over all the y's of fY|x(y|xo) = fX(xo)/fX(xo) = 1.  So the conditional density is a "legal" density.

  Conditional Expectation E(Y|xo):The mean y value, when x is a particular fixed value xo.
      Treat xo as a constant and find the Integral  of  y fY|x(y|xo) dy.
    Remember "Regression problem" in statistics:  For a particular xo, predict the "best" y-value.
           ("best" in some sense or other--average, typical...)
       In probability (the abstraction from data), E(Y|xocan play that role.
             Find it for "all" xo's, and graph it on the x-y plane.
Handout: Multivariate distributions of the Continuous Type: Example 3.7-2 ff.
We went through the handout, did not do the remaining examples in class.
--Find the conditional densities and the conditional expectations for the two functions above:
   See DPGraph pictures--slicing x  will give shape of conditional density (files are labeled by formula)
f(x,y) = x(1-y)/2, 0<x<1, 0<y<2.  fX(x) = 2x, 0<x<1.   fY(y) = (1+y)/4, 0<y<2.
f(x,y) = x+y,  0<x<1, 0<y<1.  fX(x) = x + 1/2, 0<x<1
Another? f(x,y) = 2e-x-y , y>x, x>0.
     Caution: if support of f(x,y) isn't rectangular, you have to keep track of possible values of x and y.

Astonishing(?) fact:  IF E(Y|x) is linear in x, it will coincide with the (abstraction of) the  familiar least squares regression line formula.
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New topic:  Last semester we were told that the sum of two Normal random variables is normal.
     Question:  How would you find the distribution of W = X+Y?
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HW:  Ash 8.1 covers conditional for continuous only.  Does a good job.
Multivariate ...Continuous handout:
  problem 3.7-6
  B. (this is checking the equation in the middle of the second page of the handout.)
  C. (I had hoped to do this in class but didn't get there.  The cardboard model..  Write it up.)
Ash, p. 249, #2, #5a, #3.  (These don't need to be handed in--but DO understand them.)


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