Marginal
probability function for X: pX(x) = sum down--sum over
the y's.
When the discrete distribution is represented by a formula, sometimes summing over the x's (or y's) can result in a tidy formula as well. Handout ex. 2.8.3 (see handwritten page for pictures, computations). For that distribution, X and Y are independent.
Continuous (p. 171 ff + Probability Handout)
Joint density function f(x, y)--a surface above the base x-y space.
Probability of a region R in x-y space= area
under f(x,y) and above the region.
The total probability
(area) has to = 1.
Integrals:
In the inner integral, the "other" variable acts
like a constant. Try it with g(x,y) = y, 0<x<4,
0<y<3
Find area under the curve: Dividing g by this will give a function
with area 1. Let f(x,y) = Cg(x,y) = Cy as above.C
= 1/18
Monday: Find P( X+Y<4) by integration.
Find the marginal distributions:
fY(y)
= 2y/9, 0<y<3
Are X and Y independent? Check.
NOTE: X and Y canNOT be independent unless their joint support
(region where p or f is Not 0) is rectangular!
Because if it isn't a rectangle, there will be a pair (x,y) with X
and Y having positive probabilities/densities, but the pair having 0 prob/density.
--- --- --- --- --- --- --- --- ---
HW: Handout on discrete, problem B on handwritten page,
and 5.1-1 all, 5.1-3 e, f from printed exercises
(back page).
A) Find fX(x) for
the example above, where f(x,y) = y/18 on the rectangle.
Handout on Probability, #17 and #18 (p. 2):
For this assignment, do parts a. Also determine their marginal densities
and whether X and Y are indep.
Ash p. 181, #2a For this assignment, graph the region of f, and
the region you want the prob. of. Next time finish it. (Hint--p.
164 has pictures for min and max--but in my book the text refers to the
wrong pictures (the captions are right),
#7. Do it by graphing the regions, and since all pairs
x,y are equally likely, find the prob's by proportional areas (cf. pp.
31-2, and #7 p. 35.)
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