The solution is to let Frank flacomb@wells.edu
know the exact names and locations of any
computers having this problem, and he can
reset their DNS so that Aurora and
the other internal servers are accessible to
them by name. Ken
Meanwhile I will leave a copy of the daily webpage
in a blue folder outside my door.
Additions to text:
Timeplots: watch out for extrapolation: predicting
beyond the range of the data.
Summary measures for center and spread.
Mean is the center of gravity (balance point)
of the data.
Median is the value with half above and half
below
text website http://www.whfreeman.com/ips,
scroll down to Select a Category,
choose "Statistical Applets",
Mean &Median. Convince yourself of the above.
You can use it to help answer
problem A below also.
Mean collects all the "stuff" and tells what
each individual's equal share is.
You can go from the mean
to the (aggregate) total, if you know n, the number of observations.
Quartiles: The method given here is the quick-and-dirty method
proposed by Tukey, who called them "Hinges".
Other percentiles: More exact methods exist,
but there is not universal acceptance of any.
The practical differences are small. Moore
&McCabe give a quick and dirty method at the end of example 1.15, p.
45.
Resistance: an important concept!
Boxplots The outlier rule p. 47 is good to know
about but don't bother to memorize it. If you're doing a boxplot
by hand just use your judgment about what's a suspected outlier.
NEXT CLASS: Standard deviation and variance:
I'll expect you to memorize the formula, and to be able to calculate this
by hand for up to 7 numbers.
Day 3 (Wed. Sept 5) Assigned:
(Re) Read: 1.2 thru p. 55 .Read for next class 55-58
( linear transformations)We'll also start 1.3, Normal distributions.
| Hand in:
1.42 (elections, Q) 1.63 (dog sodium, box) 1.64 (SAT, boxes) 1.50 (0's effect) Read 1.68 (guinea pigs, trimmed mean, cf. 1.27) Make a boxplot of the data, with or without outliers (you choose). We'll do trimmed means with SPSS, next week. 1.43 (SSHA M/F,IQRoutlier) (Use xbars from back of book.) Will assign next class: 1.54 (Do xbar and s by hand. Then put them in SPSS & do them.) |
Read, discuss
1.47(wealth) 1.49 &1.51(salary) A. If a distribution is skewed right, the mean will be on the /right?/left?/ of the median. |
Optional |
| Sievers home | Math251-Fall01/DayP3.htm | 4:46pm | 9/5/01 |