| Hand in
A. You are driving down the freeway and note that the number of cars that pass you is the same as the number of cars that you pass. Is your speed the median, the mean, or the midrange speed? Justify your answer. p. 36 1.31 (C-sec, 5#, boxplots) also give
the IQR for each set of doctors.
Put on separate paper and keep for Day 5
HW
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Read, to discuss
p. 74, 1.81a,b, 82(be sure you could compute it,
don't bother to do it), &83. (Walmart)Note how outliers
are listed separately ("Low" and "High" ) rather than taking huge space
for them in the stemplot. A common practice. The outlier rule is
also common for computer packages.
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Optional |
--HW questions?
P. 69, 1.74. (Hospital discharge)
--Review measures
of center
In a skewed distribution,
what is the relationship between mean and median?
P. 45, 1.46,
1.47, 1.48
Measures of Spread (dispersion,
variability) distributions
with different spreads
Range: largest
- smallest. Resistant? NO! Two observations carry
all the info; the rest could be anywhere.
Quartiles, five-number summaries,
boxplot, InterQuartile Range. (HANDOUT)
(Variance), Standard
deviation.
Quartiles Divide
data into quarters: 1st quartile Q1: 1/4 below, 3/4 above. = 25th
percentile.
(2nd quartile= median = 50th percentile)
3rd quartile Q3: 3/4
below, 1/4 above. = 75th percentile.
Computation of quartiles: Different texts, packages use different methods.Five-number summary: min, Q1, Median, Q3, max. (1, 4, 7, 9.5, 20 for the set of 8 above)
By hand: We'll use Tukey's quick and dirty: (he called them "hinges")
Take the two halves of the data you got from finding the median. Find the median of each half, using the same rule as before. (Detail. IF you had an even number of observations to start with, the data divides evenly into an upper and a lower half. IF you had an odd number to start with, you have one in the middle, the median. In this case only, you throw the median away, and use the remaining halves.)
1 3 5 6 8 8 11 20, are n=8 observations.
Median at (8+1)/2= 9/2=4 1/2th ; 1 3 5 6 8 8 11 20, M = 7
8/2 = 4 in each half: Halves are 1 3 5 6, and 8 8 11 15. The quartiles are the medians of each half; count in (4+1)/2= 2 1/2. 1 3 5 6, Q1=(3+5)/2= 4.
8 811 15. Q3= (8+11)/2= 9.5 1 3 | 5 6 | 8 8 | 11 201 3 5 6 6 8 8 11 20, are n=9 observations.
Median at (9+1)/2=10/2=5th ; 1 3 5 6 8 8 11 20, M = 6
Throw away the median. Now we have an even number again, 8 numbers
8/2 = 4 in each half: Halves are 1 3 5 6, and 8 8 11 15. Continue as before. (This is a dirty method because it gives the same quartiles for both these data sets. Quick because computation is minimal and simple.)
1 3 | 5 66 8 8 | 11 20
INTERQUARTILE RANGE = IQR= Q3 - Q1. (9.5 - 4 = 5.5for both sets above)Box (and whisker) plot: Graphical form of five number summary.
=The range of the middle half of the observations. Resistant to outliers!
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