SPSS simulation: average of spinners
which
can land on any number between 0 and 1.
Population--one spinner. distribution flat between
0 and 1, mean .49 s.d. = .29
n = 2, Average of 2 spinners is Xbar. Distribution
triangular between 0 and 1, mean .50, s.d. .21. .29/sqrt(2)
=.205
n = 4, Average of 4 spinners is Xbar. Distribution
normalish between 0 and 1, mean .50, s.d. .15. .29/sqrt(4)
=.145
n = 15, Average of 15 spinners is Xbar. Distribution
normal between 0 and 1, mean .50, s.d. .09. .29/sqrt(15) =.076
Mean of Xbars is mean of population.
Standard deviation of Xbars is s.d. of population divided by square
root of n.
As sample size increases, sampling distribution of Xbars gets more
and more normal-shaped.
(Central Limit Theorem)
Friday we will continue looking at
the Central Limit Theorem, starting here, then begin Ch. 6.
Sec. 4.3: Sampling distributions. We take
a simple random sample of size n, find the sample mean xbar. It will
be different depending on the sample, so we have a random phenomenon.
We measure the outcome as a number, the sample mean, so we have a random
variable Xbar.
Law of large numbers Let the sample
size n get bigger. Then the xbars will eventually get very
close to the population mean mu.
Usually we have a fixed sample size n.
Assume that's true from now on.
What probability distribution describes the
random phenomenon of finding Xbar from a SRS?
That is, what is the distribution of the random
variable Xbar, when the experiment is to take a simple random sample
of size n?
We'll call it the "sampling distribution of
the sample mean" = distribution of means of all possible SRS's
of size n.
Shape, center, spread, (outliers?)
Look at results from #4.40.
Things we know:
Central Limit Theorem...
How large is "large"? How approximate is
"approximate"?
If the population was close
to normal, n doesn't need to be very large.
Even if the population is
pretty weird, n=25 gives a pretty good approximation
to normal.
Pictures on overhead.
| Activstats: DO Ch 16 if you didn't.
P. 16-3 is the same as 16-2 with an added activity, + some new comments.
For next classes. Ch. 17 (optional) introduces Confidence intervals. (Alternative, read Moore 6.1) It can give you some good reinforcement for what we are doing. But many instructors (me included) think his demos with ybar in the center of the distribution may give a misleading sense of the definition of confidence interval (tho his words are right.). So if you work with this chapter, be sure to do p. 17-4 (Appendix) after p. 17-1. If YOU DIDN'T HAVE IT WEDNESDAY, DO Moore
sec. 4.3 Sampling dist. of the sample
mean:
|
| Do all of these as part
of Day 27, to be handed in Read, try now is a good idea. These problems use only the mean and standard deviation. p. 243, 4.41 (lab measurements) p. 250, 4.50 These problems use either the Central Limit theorem, or the "sample mean of n independent observations from a normal distribution has a normal distribution." theorem (both on p. 244) p. 249, 4.51 cola (you did a, now do b) p. 247, 4.44 carpet flaws. Also draw some square yards and mark some flaws. p. 250, 4.53 auto accidents More problems: p. 243 4.42 unbiasedness, sample size p. 249 4.52 hypokalemia p. 249 4.48 dust Note, the dust actually weighs 123mg, but the weighings may not be accurate enough for us to find the actual weight. "Distribution of this mean" = "Distribution of means from all possible sets of 3 weighings from these scales." When I took physics, we did not have digital scales; they were balance beams; and we weighed everything 3 times and found the average. (Have you ever gotten on the scale, said "that can't be right!" gotten off and on again a couple times?) . p.250 4.54 (labeled 4.53?)pollutants; backward from value to probability. You might want to know L so that if you tested your 125 cars and found a high value of x-bar, you would be able to compare it with L; if it was greater than L, you would go back to the manufacturer and say "I believe you sold me a batch of bad cars, because the chances of getting an average emission level this high if the exhaust system is working properly is only 1 in 100. It is more reasonable to believe the exhaust system is not working, than that we hit that 1 in 100 possibility." |
Read, to discuss | Optional |
| Sievers home | Math151-Sp02/Day26.htm | 3pm | 4/3/02 |